描述
请实现一个函数,把字符串 s
中的每个空格替换成”%20”
思路
列表推导式
class Solution:
def replaceSpace(self, s: str) -> str:
return ''.join(['%20' if c == ' ' else c for c in s])
循环
class Solution:
def replaceSpace(self, s: str) -> str:
res = ''
for i in s:
if i == ' ':
res += '%20'
else:
res += i
return res
###